This is a test of using MathJax in Blogger Note that enclosing math in single $'s does not work in the default setting for MathJax. However, you may use "\(\backslash(\)" and "\(\backslash)\)" for inline math and double dollar signs or "\(\backslash[\)" and "\(\backslash]\)" for displayed math. Examples: $(y+\sqrt z)^{-1}$ and \( \sin^2 x^2 \). And, a displayed equation is: $$\frac 2 3$$

Another displayed equation is here:

\[

\forall x \exists y (x\le y \land y\le x \leftrightarrow x=y) .

\]

To setup the MathJax capability, I added the following line to the HTML code, after the <head> command (as a single line, no line break):

<script src='http://cdn.mathjax.org/mathjax/latest/MathJax.js?config=TeX-AMS-MML_HTMLorMML' type='text/javascript'/>

You can find more information from the MathJax website about this at http://www.mathjax.org/docs/1.1/start.html.

For slightly different ways to set up MathJax with Blogger, see http://holdenweb.blogspot.com/2011/11/blogging-mathematics.html, or

http://irrep.blogspot.com/2011/07/mathjax-in-blogger-ii.html.

However, so far, I do not have MathJax working in the comments. For example: \( e^{i\pi} = -1 \).

ReplyDeleteSuggestions on how to fix this are welcome.

Correction: The mathematics will appear correctly once the comment is posted, but it does not appear correctly in the preview window when you are preparing your comment.

ReplyDeleteTest: \(\sin x\)

ReplyDelete\begin{matrix}

ReplyDeletea & b\cr

c & d

\end{matrix}

a < b

ReplyDelete\begin{matrix} a & b\cr c & d \end{matrix}

ReplyDelete\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]

ReplyDelete\def\arccosAlt{\cos^{-1}} so that $\arccosAlt(x)$

ReplyDelete$$\cosh^2 x - \sinh^2 x = 1$$

ReplyDeleteTesting only

\( \sin^2 x + \cos^2 x = 1 \)

ReplyDelete\sin^2 x + \cos^2 x = 1

ReplyDelete\cosh^2 x - \sinh^2 x = 1

ReplyDelete\( \cosh^2 x - \sinh^2 x = 1 \)

ReplyDelete\(\sin x\)

ReplyDelete\(\sin x)

\(\dim T^2V^*=n^2\)

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDelete1.why \(\tilde f (z)={\bar \psi}^{-1}(f(\phi(z)))\) but not \(\tilde f (z)={\psi}^{-1}(f(\phi(z)))\)?

ReplyDelete2.do we have \(d\tilde \phi_x\)? if yes, what does it mean?

3.can u show us how \(Tf_p\) is independent of the choice of \(\phi\) and \(\psi\)

This comment has been removed by the author.

ReplyDeleteTesting..

ReplyDelete\[\LaTeX\]

Test: \(x^2 + y^2 = z^2\)

ReplyDeleteThis comment has been removed by the author.

ReplyDelete$x^2$

ReplyDelete\(10^100\)

ReplyDelete\(10^{100}\)

ReplyDeleteI'd like to have a \( 1/2 \) glass of common sense please.

ReplyDeleteI'd like to have a \[ 1/2 \] glass of common sense please.

ReplyDeleteBelieve it or not, I'm using MathJax with a 'Classic' Blogger template.

ReplyDelete\[\left ( \alpha +\beta \right )^2 = \alpha ^2+\beta ^2+2\alpha \beta \]

ReplyDelete\( \sum_{i=0}^{n} 2^i = 2^{n+1}\)

ReplyDelete\( \sum_{i=0}^n 2^i = 2^{n+1}-1\)

DeleteThis comment has been removed by the author.

ReplyDelete\[ \frac{13333}{2} \]

ReplyDelete\[

ReplyDelete\begin{aligned}

\nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} \\ \nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \\

\nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \\

\nabla \cdot \vec{\mathbf{B}} & = 0 \end{aligned}

\]

This comment has been removed by the author.

ReplyDelete\((y+\sqrt z)^{-1}\)

ReplyDeletetest

ReplyDelete$\displaystyle \int_0^{\infty} \sqrt{4x} \, e^{-x} \, dx$ = $2\displaystyle \int_0^{\infty} \sqrt{x} \, e^{-x} \, dx = 2 \Gamma\left(\frac{3}{2}\right) = 2 \frac{1}{2} \, \Gamma\left(\frac{1}{2}\right) = \sqrt{\pi}$

$$2\displaystyle \int_0^{\infty} \sqrt{x} \, e^{-x} \, dx = 2 \Gamma\left(\frac{3}{2}\right) = 2 \frac{1}{2} \, \Gamma\left(\frac{1}{2}\right) = \sqrt{\pi}$$

DeleteThis comment has been removed by the author.

Delete\[\bar{x}=\frac{1}{n}\sum\limits_{i=1}^{n}{x_i}\]

ReplyDeleteLearn a complete LaTeX on Udemy: https://www.udemy.com/latex-for-dissertation-publication-and-presentation/?couponCode=CAD15COUPON

ReplyDeleteIs this helpful?

DeleteThis is a complete LaTeX course, 3.5hours video. Lot of templates.

DeleteThis comment has been removed by the author.

ReplyDelete$P_{mkn}$

ReplyDelete$$P_{mkn}$$

DeleteFantastic I done it by your way

ReplyDelete